A wire of length 95 m is cut into three pieces such that the length of each piece is 50 % greater than the previous piece. What is the length of the largest piece?
A 36 m B 42 m C 45 m D 46 m E 48 m
C
Let v be the length of the smallest piece. Then the middle piece has length 3 2 v and the largest has length 3 2 × 3 2 v = 9 4 v. So the total length is 9 4 v + 3 2 v + v = 19 4 v and hence v = 20 m and the longest piece has length 9 4 v, that is 45 m.
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